The area of a triangle is one-half times the base times the height.
Examine the areas of both figures.
| Areafigure 1 | = | ab | 
|
| Areafigure 2 | = | (ka)(kb) | 
|  | = | kk(ab) | 
|  | = | k2(Areafigure 1) | 
				So, the area of the new rectangle is 9 times the area of the original rectangle.